(9x)^2+(16x)^2=5.9^2

Solution for (9x)^2+(16x)^2=5.9^2 equation:

(9x)^2+(16x)^2=5.9^2

We move all terms to the left:

(9x)^2+(16x)^2-(5.9^2)=0

We add all the numbers together, and all the variables

25x^2-34.81=0

a = 25; b = 0; c = -34.81;
Δ = b2-4ac
Δ = 02-4·25·(-34.81)
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-59}{2*25}=\frac{-59}{50}
=-1+9/50
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+59}{2*25}=\frac{59}{50}
=1+9/50
$